open TELEMAC-MASCARET The mathematically superior suite of solvers

Hey,

How is what you must write a TUBES DATA FILE (FICHIER DE DONNEES DES BUSES)?
I supposed like with siphon we have a specific nomenclature for this type of file

Thank for your help

Regards

Marine

Hi
You will find an example in the validation test case number 039-Bridge

Hope this helps

Hello,

In the section training and tutorials and the section validation of the website, there are just the validation test for the V6P1 version of Telemac, there are not for the V6P2. So I don't see the test case number 039 when I download these two files.(www.opentelemac.org/index.php?option=com...&catid=29&Itemid=137 and www.opentelemac.org/index.php?option=com...y&catid=4&Itemid=122)

Thank for your help

Regards

Marine

Hi
The validation test case should be available with the repository.
Have a look on the svn sources

Regards

hum I just find the sources in the svn sources and not the validation test case maybe I don't know how I need to use this. Generally, I don't work with svn sources

Regards

Marine

Hi
There is a specific tag for the validation case
I add a zip of the test case here



Hope this helps

ok thank you

Best regards

Marine

Hello!

I have tested the new tube fonction with the 039_bridge test case.
I am a bit suprised by the result shown.

Here a the main parameters (there are 2 identical tubes):
- S1=8,66
- S2=7,10
- RD1=RD2=1
- HAU=1,5
- LAR=2,5
- Ce=0,5
- Cs=1,0
- L=0,2

The computed discharge through each tube is ca 25 m3/s.

This result is obtained by the following formula (buse.f):
Q = SECT * SQRT( 2.D0*GRAV*(S1-S2)/(CE1+L) )

I would have expected the last one to be used instead, valid when both inlet and outlet are submerged (which is the case here):
Q = SECT * SQRT( 2.D0*GRAV*(S1-S2)/(L+CS2+CE1) ), which here only gives a discharge of ca 16 m3/s using the computed (S1-S2).

When looking at the first equation, not using CS2 coefficient with the given (S1-S2) implies an equivalent orifice coefficient of 1,19, which seems strange (V cannot be > (2gh)^0,5), whereas it is 0,77 in the last one, which is logical.

Being not familiar with programming, I am not sure how water surface profiles and each formula are linked.

A last question: why didn't you use the same submerged weir formula than the one used in loinoy.f?

Thanks in advance,
PL

Hi,

Just to add that only Q = SECT * SQRT( 2.D0*GRAV*(S1-S2)/(L+CS2+CE1) ) is treated in siphon.f, when S1 and S2 are higher than siphon's upper height. Q = 0 otherwise.
It therefore should be this formula to be used for the validation case. Or I am missing something?

Thanks in advance,
Pierre-Louis

Hi !

Did someone have a look at these questions yet?

Thanks in advance!
PL