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TOPIC: Problems with MOC for k-e turbulence model

Problems with MOC for k-e turbulence model 8 years 5 months ago #21777

  • konsonaut
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Hello,

I'm simulating a laboratory case using a high mesh resolution. The cell sizes are rather small (volumes around 1.D-6 m³) and there are no tidal flats.
Everything works fine but when I switch to the MOC scheme for the advection for k and e, after some time steps I get exceeding number of iterations.

I would be glad for any hints.


Best regards,
Clemens
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Problems with MOC for k-e turbulence model 8 years 5 months ago #21778

  • riadh
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Hello Clemens

you have simply to reduce your time step ;)

Kind regards


Riadh
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Problems with MOC for k-e turbulence model 8 years 5 months ago #21779

  • konsonaut
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Hi Riadh,

unfortunately decreasing the time step to 1/10 of the employed time step when using another scheme doesn't help. I'm using v7p1r1.
The problem arises only when using MOC for the advection of k-e model. For example the combination MOC for velocities and MURD for k-e works well.

Here my steering file with a time step of 0.005s.
N.B.: all the other schemes work well with a time step of 0.05s!

________________________________________________________________
PARALLEL PROCESSORS =4
/
/ EQUATIONS
/
TURBULENCE REGIME FOR THE BOTTOM =2
TURBULENCE REGIME FOR LATERAL SOLID BOUNDARIES =2
COEFFICIENT FOR HORIZONTAL DIFFUSION OF VELOCITIES =1.E-6
COEFFICIENT FOR VERTICAL DIFFUSION OF VELOCITIES =1.E-6
HORIZONTAL TURBULENCE MODEL =3
VERTICAL TURBULENCE MODEL =3
LAW OF BOTTOM FRICTION =5
LAW OF FRICTION ON LATERAL BOUNDARIES =5
FRICTION COEFFICIENT FOR THE BOTTOM =0.0005
FRICTION COEFFICIENT FOR LATERAL SOLID BOUNDARIES =0.0005
NON-HYDROSTATIC VERSION =YES
OPTION FOR THE BOUNDARY CONDITIONS OF K-EPSILON =1
/
/ EQUATIONS, ADVECTION
/
SCHEME FOR ADVECTION OF VELOCITIES =1
SCHEME FOR ADVECTION OF K-EPSILON =1
/
/ EQUATIONS, BOUNDARY CONDITIONS
/
VELOCITY VERTICAL PROFILES =2;2 /2:logarithmic
VELOCITY PROFILES =1;1
/
/ EQUATIONS, INITIAL CONDITIONS
/
INITIAL ELEVATION =0.189
INITIAL CONDITIONS ='CONSTANT ELEVATION'
PRESCRIBED FLOWRATES =0.0;0.0453
PRESCRIBED ELEVATIONS =0.189;0.0
/
/ INPUT-OUTPUT, FILES
/
/ LIQUID BOUNDARIES FILE ='Hydrograph_to_steady.txt'
GEOMETRY FILE ='mesh.slf'
BOUNDARY CONDITIONS FILE ='BOTTOM_BCmesh.cli'
3D RESULT FILE ='r3d_MOC_ts0.005.slf'
2D RESULT FILE ='r2d_MOC_ts0.005.slf'
/
/ INPUT-OUTPUT, GRAPHICS AND LISTING
/
LISTING PRINTOUT PERIOD =120
VARIABLES FOR 3D GRAPHIC PRINTOUTS ='Z,U,V,W,K,EPS'
GRAPHIC PRINTOUT PERIOD =3000
VARIABLES FOR 2D GRAPHIC PRINTOUTS ='U,V,H,S,B,US'
MASS-BALANCE =true
/
/ NUMERIC PARAMETERS
/
NUMBER OF HORIZONTAL LEVELS =10
/
/ NUMERICAL PARAMETERS
/
FREE SURFACE GRADIENT COMPATIBILITY =0.9
TIME STEP =0.005
NUMBER OF TIME STEPS =120000
/ IMPLICITATION FOR DEPTH =1.0
/ IMPLICITATION FOR VELOCITIES =1.0
________________________________________________________________

Best regards,
Clemens
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Problems with MOC for k-e turbulence model 8 years 5 months ago #21788

  • jmhervouet
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Hello Clemens,

I am afraid that you are hindered by the fact that a number of subroutines use the threshold of volume=1.E-6 to decide that there is a tidal flat. For example in that case the diffusion must be stopped or it may give infinite values, so you have such threshold in mt02pp.f.

With best regards,

Jean-Michel Hervouet
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